Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.4 Cross Products - 11.4 Exercises - Page 797: 29

Answer

\[{\mathbf{u}} \times {\mathbf{v}} = \left\langle { - 30,18,9} \right\rangle {\text{ and }}{\mathbf{u}} \times {\mathbf{v}} = \left\langle {30, - 18, - 9} \right\rangle \]

Work Step by Step

\[\begin{gathered} {\mathbf{u}} = \left\langle {3,5,0} \right\rangle ,\,\,\,{\mathbf{v}} = \left\langle {0,3, - 6} \right\rangle \hfill \\ \hfill \\ {\text{Calculate }}{\mathbf{u}} \times {\mathbf{v}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left| {\begin{array}{*{20}{c}} {\mathbf{i}}&{\mathbf{j}}&{\mathbf{k}} \\ 3&5&0 \\ 0&3&{ - 6} \end{array}} \right| \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left| {\begin{array}{*{20}{c}} 5&0 \\ 3&{ - 6} \end{array}} \right|{\mathbf{i}} - \left| {\begin{array}{*{20}{c}} 3&0 \\ 0&{ - 6} \end{array}} \right|{\mathbf{j}} + \left| {\begin{array}{*{20}{c}} 3&5 \\ 0&3 \end{array}} \right|{\mathbf{k}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left( { - 30 - 0} \right){\mathbf{i}} - \left( { - 18 - 0} \right){\mathbf{j}} + \left( {9 - 0} \right){\mathbf{k}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = - 30{\mathbf{i}} + 18{\mathbf{j}} + 9{\mathbf{k}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left\langle { - 30,18,9} \right\rangle \hfill \\ \hfill \\ {\text{Calculate }}{\mathbf{v}} \times {\mathbf{u}} \hfill \\ {\mathbf{v}} \times {\mathbf{u}} = \left| {\begin{array}{*{20}{c}} {\mathbf{i}}&{\mathbf{j}}&{\mathbf{k}} \\ 0&3&{ - 6} \\ 3&5&0 \end{array}} \right| \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left| {\begin{array}{*{20}{c}} 3&{ - 6} \\ 5&0 \end{array}} \right|{\mathbf{i}} - \left| {\begin{array}{*{20}{c}} 0&{ - 6} \\ 3&0 \end{array}} \right|{\mathbf{j}} + \left| {\begin{array}{*{20}{c}} 0&3 \\ 3&5 \end{array}} \right|{\mathbf{k}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left( {0 + 30} \right){\mathbf{i}} - \left( {0 + 18} \right){\mathbf{j}} + \left( {0 - 9} \right){\mathbf{k}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = 30{\mathbf{i}} - 18{\mathbf{j}} - 9{\mathbf{k}} \hfill \\ {\mathbf{u}} \times {\mathbf{v}} = \left\langle {30, - 18, - 9} \right\rangle \hfill \\ \end{gathered} \]
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