Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.2 Vectors in Three Dimensions - 11.2 Exercises - Page 777: 7

Answer

Point $(0,0,4)$ is farther from the origin

Work Step by Step

Point $(3,-1,2)$ Distance for Origin $= \sqrt {(3)^2 + (-1)^2 + (2)^2} = \sqrt {14}$ Point $(0,0,4)$ Distance for Origin $= \sqrt {(0)^2 + (0)^2 + (4)^2} = \sqrt {16}$
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