Answer
$${\text{Click to see the graph}}$$
Work Step by Step
$$\eqalign{
& 12x = 5{y^2} \cr
& {y^2} = \frac{{12}}{5}x \cr
& {\text{The equation is in the form }}{y^2} = 4px \cr
& {y^2} = \frac{{12}}{5}x:{\text{ }}{y^2} = 4px \cr
& \frac{{12}}{5}x = 4px \cr
& p = \frac{3}{5} \cr
& {\text{The focus of a parabola of the form }}{y^2} = 4px{\text{ is}} \cr
& {\text{Focus }}\left( {p,0} \right) \Rightarrow {\text{Focus }}\left( {\frac{3}{5},0} \right) \cr
& {\text{The directrix of a parabola of the form }}{y^2} = 4px{\text{ is}} \cr
& x = - p \Rightarrow x = - \frac{3}{5} \cr
& {\text{Graph}} \cr} $$
