#### Answer

The function is
$$f(x)=x-5.$$
The graph is in the figure below

#### Work Step by Step

The equation of the linear function passing through points $P(x_1,y_1)$ and $Q(x_2,y_2)$ is given by
$$y=\frac{y_2-y_1}{x_2-x_1}(x-x_1)+y_1.$$
Using the data given in the problem
$$x_1=2\quad y_1=-3,\quad x_2=5,\quad y_2=0$$
we get
$$y=\frac{0-(-3)}{5-2}(x-2)+(-3)=x-2-3=x-5$$
so our linear function is
$$f(x)=x-5.$$
Drawing the line through points $(2,-3)$ and $(5,0)$ we get the required graph