Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 9 - Differential Equations - Review - True-False Quiz - Page 674: 2


$\bf True$.

Work Step by Step

$\bf True$. $f(x)=y=\frac{lnx}{x}$ $y'=\frac{1-lnx}{x^{2}}$ Now, $x^{2}y'+xy=x^{2}\frac{1-lnx}{x^{2}}+x\frac{lnx}{x}$ $=1-lnx+lnx$ $=1$
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