#### Answer

$4\sqrt{5}$

#### Work Step by Step

$y = 2x-5$
$L = \int^{3}_{-1} \sqrt{1+(\frac{dy}{dx})^2}dx = \int^{3}_{-1}\sqrt{1+(2)^2}dx = \sqrt{5}[3-(-1)] = 4\sqrt{5} $

Published by
Cengage

ISBN 10:
1285740629

ISBN 13:
978-1-28574-062-1

$4\sqrt{5}$

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