Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 7 - Techniques of Integration - 7.5 Strategy for Integration - 7.5 Exercises: 1

Answer

$-\ln (1-\sin x)+C$

Work Step by Step

$\int\frac{\cos x}{1-\sin x}dx$ Let $u=1-\sin x$. Then $du=-\cos x dx$, and $\cos xdx=-du$. $=\int\frac{-du}{u}$ $=-\ln |u|+C$ $=-\ln |1-\sin x|+C$
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