Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.8 Indeterminate Forms and I'Hospital's Rule - 6.8 Exercises - Page 499: 6



Work Step by Step

From the given graph, we have $\lim\limits_{x \to 2} \dfrac{f(x)}{g(x)} = \lim\limits_{x \to 2} \dfrac{1.5(x-2)}{(2-x)} = \dfrac{0}{0}$ This shows is an indeterminate form. Thus, applying L'Hospital, we get $= \lim\limits_{x \to 2} \dfrac{1.5(x-2)}{(-1)(x-2)}$ $=-1.5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.