Answer
$2\sinh x\cosh x$
Work Step by Step
Given: $g(x)=\sinh^2 x$
Now, $g'(x)=\dfrac{d}{dx}(\sinh^2 x)$
On applying chain rule, we have
$g'(x)=(\dfrac{d\sinh^2 x}{d \sinh x})(\dfrac{d\sinh x}{dx})$
or, $=(2\sinh x)(\cosh x)$
or, $=2\sinh x\cosh x$
