Answer
$y=3x-9$
Work Step by Step
The slope of the tangent line at $(3,0)$ is:
$$y'=\frac{2x-3}{x^{2}-3x+1}=\frac{3}{1}=3$$
So the tangent line is:
$$y=0+3(x-3)$$
$$y=3x-9$$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.4 Derivatives of Logarithmic Functions - 6.4 Exercises - Page 437: 37
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