Calculus 8th Edition

$f^{-1}(x)=\frac{x^{2}-3}{4}$
Calculate the inverse of the function $f(x)=\sqrt {4x+3}$ Write $y=f(x)$ $y=\sqrt {4x+3}$ Solve this equation for x in terms of y to get the inverse function. $x=\frac{y^{2}-3}{4}$ To express $f^{-1}(x)$ as a function of x,interchange x and y. The resulting equation is $y=\frac{x^{2}-3}{4}$ Therefore, the inverse of the function $f^{-1}(x)=y=\frac{x^{2}-3}{4}$ The graph of the functions $f(x)=\sqrt {4x+3}$ and $f^{-1}(x)=\frac{x^{2}-3}{4}$ along the line $y=x$ on the same screen is depicted below: