Answer
$ \frac{T^5}{5} - 4T^2 + 7T$
Work Step by Step
First, we evaluate the integral, which give us $ \frac{x^5}{5} - 4x^2 + 7x \Biggr|_{0}^{T}$
Then, we substitute the bounds of integration into x and get $ \frac{T^5}{5} - 4T^2 + 7T - (0)$
So our final answer is $ \frac{T^5}{5} - 4T^2 + 7T$
