Calculus 8th Edition

$$f(x)=4 \sqrt{x}-6 x^{2}+3=4 x^{1 / 2}-6 x^{2}+3$$ The most general antiderivative of the given function is $$F(x)=\frac{8}{3} x^{3 / 2}-2 x^{3}+3 x+C$$
$$f(x)=4 \sqrt{x}-6 x^{2}+3=4 x^{1 / 2}-6 x^{2}+3$$ The general anti-derivative of $f(x)=4 \sqrt{x}-6 x^{2}+3,$ is \begin{aligned} F(x) &=4\left(\frac{2}{3} x^{3 / 2}\right)-6\left(\frac{1}{3} x^{3}\right)+3 x+C \\ & =\frac{8}{3} x^{3 / 2}-2 x^{3}+3 x+C \end{aligned}