Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 3 - Applications of Differentiation - Review - Exercises - Page 286: 10

Answer

$$-\infty$$

Work Step by Step

Given $$\lim\limits_{x \to -\infty} (x^2+x^3) $$ Then \begin{align*} \lim_{x \to -\infty} (x^2+x^3) &=\lim_{x \to -\infty} x^2(1+x ) \\ &=\lim_{x \to -\infty} x^2\lim_{x \to -\infty}(1+x ) \\ &=(\infty)(1-\infty)\\ &=-\infty \end{align*}
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