Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 3 - Applications of Differentiation - 3.9 Antiderivatives - 3.9 Exercises - Page 282: 20

Answer

$$F(x) = x-2\cos x+6x^{1/2} +C$$

Work Step by Step

Given $$f(x) = 1+2\sin x+3/\sqrt{x}= 1+2\sin x+3x^{-1/2}$$ Then by using table 2 if $f(x)= x^n\ \to\ \ F(x) = \frac{x^{n+1}}{n+1} +C$ and if $f(x)=\sin x\ \to\ \ F(x) =-\cos x +C$ Hence \begin{align*} F(x)&= x-2\cos x+\frac{3}{1/2}x^{1/2}+C \\ &= x-2\cos x+6x^{1/2} +C \end{align*} To check \begin{align*} F'(x) &= 1+2\sin x+3x^{-1/2} \\ &= 1+2\sin x+3/\sqrt{x}\\ &=f(x) \end{align*}
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