Answer
Use $g(x) = -f(x)$
Work Step by Step
If $f$ has a local minimum at $c$, then the function $g(x) = -f(x)$ has a local maximum at $c$, so we have:
$g'(c) = 0$ by the case of Fermat's Theorem proved in the text.
Thus $f'(c) = -g'(c) = 0$.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 3 - Applications of Differentiation - 3.1 Maximum and Minimum Values - 3.1 Execises - Page 213: 71
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