#### Answer

TRUE

#### Work Step by Step

Given: $f(x)=(x^{6}-x^{4})^{5}$
If this were multiplied out, the highest power term would be
$(x^{6})^{5}=x^{30}$
The derivative of this term would be
$f'(x)=30x^{29}...$
$f''(x)=30.29x^{28}...$
$f'''(x)=30.29.28x^{27}...$
so on
$f^{30}(x)=30!x^{0}=30!$
and the derivative of a constant is $0$, so
$f^{31}(x)=0$
Hence, the given statement is true.