Answer
For $x^4+x^2y^2+y^3=5$ find $\frac{dy}{dx}$
Work Step by Step
Differentiate both sides with respect to x
$4x^3+2xy^2+x^22y\frac{dy}{dx}+3y^2\frac{dy}{dx}=0$
Isolate $\frac{dy}{dx}$
$\frac{dy}{dx}(x^22y+3y^2)=-4x^3-2xy^2$
$\frac{dy}{dx}=\frac{-4x^3-2xy^2}{x^22y+3y^2}$