Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.2 The Derivative as a Function - 2.2 Exercises - Page 130: 65

Answer

$Φ$ $\approx$ $63 °$

Work Step by Step

$m$ = $\frac{Δy}{Δx}$ = $tanΦ$ $0$ $\lt$ $Φ$ $\lt$ $\frac{\pi}{2}$ $f(x)$ = $x^{2}$ $f'(x)$ = $2x$ So the slop of the tangent to the curve at the point (1,1) is 2 $m$ = $tanΦ$ $2$ = $tanΦ$ $Φ$ = $tan^{-1}2$ $Φ$ $\approx$ $63 °$
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