#### Answer

See the graphs

#### Work Step by Step

Analyzing the graph:
Step 1:
Let take a look in quadrant 2 and let us choose arbitrary x and y
points
Step 2: $x_{2}>x_{1}$ and $y_{2}0$ and $y_{2}-y_{1}<0$
Step4:
as show any computed difference value of y will end in quadrant
3 in the black for the same domain values.
Step 5:
as we get $y_{2}=y_{1}$, then slope is zero. That is when we
reach the x axis and that is when the red line starts.
Step 6:
The red section labeled on the graph says that while it is true that
$y_{2}-y_{1}<0$ before the slope is zero,starting from that point
on we have: $x_{2}-x_{1}>0$ and $y_{2}-y_{1}>0$
Which means as shown any computed difference value of y
will end in quadrant 2 in the for the same domain values until
$y_{2}-y_{1}=0$, slope is zero.
Step7:
In quadrant 1: $x_{2}-x_{1}>0$ and $y_{2}-y_{1}>0$. As the blue label states, any compute difference y values will end in quadrant 1 until $y_{2}-y_{1}=0$, slope is zero.
Step8
Quadrant 4: $x_{2}-x_{1}>0$ and $y_{2}-y_{1}<0$
As shown in green label.
Following the same steps #1-8, it slould be easy to show the derivatives of the graphs for: B, C, and D.