## Calculus 8th Edition

$y=9x-15$
$y=x^3-3x+1, (2,3)$ $y'=3x^2-3$ Plug in the x-value to find the slope of the tangent line at the given point. $y'=3(2)^2-3$ $y'=9$ Write the equation in point-slope form. $y-3=9(x-2)$ Rewrite into standard form. $y=9x-15$