Answer
$y=9x-15$
Work Step by Step
$y=x^3-3x+1, (2,3)$
$y'=3x^2-3$
Plug in the x-value to find the slope of the tangent line at the given point.
$y'=3(2)^2-3$
$y'=9$
Write the equation in point-slope form.
$y-3=9(x-2)$
Rewrite into standard form.
$y=9x-15$
