Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.1 Derivatives and Rates of Change - 2.1 Exercises - Page 113: 6



Work Step by Step

$y=x^3-3x+1, (2,3)$ $y'=3x^2-3$ Plug in the x-value to find the slope of the tangent line at the given point. $y'=3(2)^2-3$ $y'=9$ Write the equation in point-slope form. $y-3=9(x-2)$ Rewrite into standard form. $y=9x-15$
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