Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 17 - Second-Order Differential Equations - 17.1 Second-Order Linear Equations - 17.1 Exercises: 4

Answer

$y=c_{1}e^{3x}+c_{2}e^{-4x}$

Work Step by Step

$r^{2}+r-12=0$ $(r-3)(r+4)=0$ So general formula and general solution add up to make the auxiliary equation which is $ar^2+by+c=0$ therefore the final answer would be $y=c_{1}e^{3x}+c_{2}e^{-4x}$
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