Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 16 - Vector Calculus - 16.2 Line Integrals - 16.2 Exercises - Page 1124: 15



Work Step by Step

$I=\int_{C}z^2 dx+x^2 dy+y^2 dz$ $=\int_{0}^{1} (2t)^2(3 dt) +(1+3t)^2 (1 dt) +(t)^2 (2 dt)$ $=\int_{0}^{1} (12t^2) dt +(1+6t+9t^2) dt +(2t)^2 dt$ $=\int_{0}^{1} 23t^2+6t+1 dt$ $=[\dfrac{23t^3}{3}+3t^2+t]_0^1$ $=\dfrac{35}{3}$
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