Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 13 - Vector Functions - 13.4 Motion in Space: Velocity and Acceleration - 13.4 Exercises - Page 918: 20


$m(6ti+2j+6tk)$ or, $6tmi+2mj+6mtk$

Work Step by Step

Determine the force of a particle with mass $m$ . Apply Newton's Second law of kinematics. Force vector: $F(t)=ma(t)$ As we are given that $r(t)=t^3i+t^2j+t^3k$ $v(t)=r'(t)=3t^2i+2tj+3t^2k$ and $a(t)=v'(t)=6ti+2j+6tk$ Consider the force vector equation such as $F(t)=ma(t)=m(6ti+2j+6tk)$ $F(t)=m(6ti+2j+6tk)$ or, $F(t)=6tmi+2mj+6mtk$
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