## Calculus 8th Edition

Published by Cengage

# Chapter 12 - Vectors and the Geometry of Space - Review - True-False Quiz - Page 882: 15

FALSE

#### Work Step by Step

Given: $6x-2y+4z=1$ The normal vector of the plane is $6x-2y+4z=1$ $\lt 6,-2, 4\gt$ Divide by 2 $\lt 3,-1, 2\gt$ Thus the normal vectors are not parallel either they are orthogonal or perpendicular. Hence, the statement is false.

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