Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 12 - Vectors and the Geometry of Space - Review - Exercises - Page 883: 15


$x=4-3t,y=-1+2t,z= 2+3t$

Work Step by Step

Given: $A(4,-1,2), B(1,1,5)$ The direction of the vectors is $\lt-3,2,3 \gt$ Formula for a line $r=r_{0}+tv$ where $r_{0}$ is the starting point vector and $v$ is the direction vector. $r=\lt 4,-1,2\gt+t \lt -3,2,3\gt$ Therefore, the parametric equations of the line are: $x=4-3t,y=-1+2t,z= 2+3t$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.