Answer
$7$
Work Step by Step
Let
$\bar{a}=<5,-2>$
$\bar{b}=<3,4>$
If given the vectors $\bar{a}=$ and $\bar{b}=$, we have:
$$\bar{a}\cdot \bar{b}=a_1b_1+a_2b_2.$$
We calculate $\bar{a}\cdot\bar{b}$:
$$\bar{a}\cdot\bar{b}=5\cdot 3+(-2)\cdot 4=15-8=7$$
