## Calculus 8th Edition

$(x-3)^2+(y-8)^2+(z-1)^2=30$
First we find the radius of the sphere by finding the distance from the center to one of the points: $r=\sqrt{(3-4)^2+(8-3)^2+(1--1)^2}=\sqrt{(-1)^2+5^2+2^2}=\sqrt{1+25+4}=\sqrt{30}$ Next we use the equation of the sphere with the center point and radius: $(x-3)^2+(y-8)^2+(z-1)^2=(\sqrt{30})^2=30$