## Calculus 8th Edition

$\lim\limits_{n \to \infty}(a_{n+3}-a_{n})=\lim\limits_{n \to \infty}a_{n+3}-\lim\limits_{n \to \infty}a_{n}$ Therefore, $\lim\limits_{n \to \infty}(a_{n+3}-a_{n})=2-2=0$ Hence, the statement is true.