Answer
radius of convergence of $\sum_{k=0}^{\infty} (c_{n}+d_{n})x^{n}=2$
Work Step by Step
$\sum_{k=0}^{\infty} c_{n}(x_{0}^{n}=\sum_{k=0}^{\infty} (c_{n}+d_{n})(x_{0})^{n}-\sum_{k=0}^{\infty} d_{n}(x_{0}^{n}) $ is convergent.
Hence, the radius of convergence of $\sum_{k=0}^{\infty} (c_{n}+d_{n})x^{n}=2$
