## Calculus 8th Edition

a) $I_{1}=0$ $I_{2}=0.25$ $I_{3}=0.75$ $I_{4}=1.50$ $I_{5}=2.50$ $I_{6}=3.76$ b) $I_{24}=70.28$
a) $I_{n}=100(\frac{(1.0025)^{n}-1}{0.0025}-n)$ $I_{1}=100(\frac{(1.0025)^{1}-1}{0.0025}-1)=0$ $I_{2}=100(\frac{(1.0025)^{2}-1}{0.0025}-2)=0.25$ $I_{3}=100(\frac{(1.0025)^{3}-1}{0.0025}-3)=0.75$ $I_{4}=100(\frac{(1.0025)^{4}-1}{0.0025}-4)=1.50$ $I_{5}=100(\frac{(1.0025)^{5}-1}{0.0025}-5)=2.50$ $I_{6}=100(\frac{(1.0025)^{6}-1}{0.0025}-6)=3.76$ b) After 2 years $n=24$ $I_{24}=100(\frac{(1.0025)^{24}-1}{0.0025}-24)=70.28$