Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - 10.5 Conic Sections - 10.5 Exercises - Page 721: 49

Answer

$\dfrac{x^2}{3763600}+\dfrac{y^2}{3753196}=1$

Work Step by Step

Since, $u-v=2c$ ... (1) $v=1728+110=1838$ $u=1728+314=2042$ Equation (1) become, $2c=2042-1838$ or, $c=102$ $c+v=a$ ... (2) Plug the values for $c=102$ and $v=1838$, in equation (2) we have $a=102+1838=1940$ Also, $b=\sqrt {1940^2-102^2}=1937$ Hence, $\dfrac{x^2}{3763600}+\dfrac{y^2}{3753196}=1$
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