## Calculus 8th Edition

$\frac{1±\sqrt 5}{2}$
when x $\lt$ a f(x) =x+1 is continous (basic function) when x $\gt$ a f(x)=$x^{2}$ is also continous (basic function) at x=a, we have $\lim\limits_{x \to a^{-}}$ f(x)= a+1 $\lim\limits_{x \to a^{+}}$ f(x)=$a^{2}$ To make f contiunous at x=a $\lim\limits_{x\to a^{-}}$ f(x) = $\lim\limits_{x \to a^{+}}$ f(x) a+1=$a^{2}$ a=$\frac{1±\sqrt 5}{2}$