## Calculus 8th Edition

$[-3, -2), (-2, -1), (-1,0], (0,1)$, and $(1, 3]$
See Definition, p.85. A function $f$ is continuous on an interval if it is continuous at every number in the interval. (If $f$ is defined only on one side of an endpoint of the interval, we understand continuous at the endpoint to mean continuous from the right or continuous from the left.) ------------------ From the graph, $-3$ and $3$ are endpoints, g is discontinuous at $-2, -1, 0,$ and $1.$ $g$ is continuous on the intervals $[-3, -2), (-2, -1), (-1,0], (0,1)$, and $(1, 3]$