#### Answer

$[-3, -2), (-2, -1), (-1,0], (0,1)$, and $(1, 3]$

#### Work Step by Step

See Definition, p.85.
A function $f$ is continuous on an interval if it is continuous at every number in the interval.
(If $f$ is defined only on one side of an endpoint of the interval, we understand continuous at the endpoint to mean continuous from the right or continuous from the left.)
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From the graph,
$-3$ and $3$ are endpoints,
g is discontinuous at $-2, -1, 0, $ and $1.$
$g$ is continuous on the intervals
$[-3, -2), (-2, -1), (-1,0], (0,1)$, and $(1, 3]$