#### Answer

x $\ne$ $\pi$/4 + k$\pi$, where k is any integer.

#### Work Step by Step

We must have: 1 - tan x $\ne$ 0. So, tan x $\ne$ 1.
But, tan x = 1 for x = $\pi$/4 + k$\pi$, where k is any integer.

Published by
Cengage

ISBN 10:
1285740629

ISBN 13:
978-1-28574-062-1

x $\ne$ $\pi$/4 + k$\pi$, where k is any integer.

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