## Calculus 8th Edition

(a)$(-5,3)$ (b)$(-5,-3)$
(a) the point (-5,3) must be on the graph. because even function satisfies $f(-x)=f(x)$ for every number x in the domain. and if $f(5)=3$ it must be that $f(-5)=3$. (b) the point (-5,-3) must be on the graph. because even function satisfies $f(-x)=-f(x)$ for every number x in the domain. and if $f(5)=3$ it must be that $f(-5)=-f(5)=-3$.