#### Answer

(a)$(-5,3)$
(b)$(-5,-3)$

#### Work Step by Step

(a) the point (-5,3) must be on the graph.
because even function satisfies $f(-x)=f(x)$ for every number x in the domain.
and if $f(5)=3$ it must be that $f(-5)=3$.
(b) the point (-5,-3) must be on the graph.
because even function satisfies $f(-x)=-f(x)$ for every number x in the domain.
and if $f(5)=3$ it must be that $f(-5)=-f(5)=-3$.