Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - 1.1 Four Ways to Represent a Function - 1.1 Exercises - Page 19: 2

Answer

True $f=g$

Work Step by Step

This is true because $\frac{x^{2}-1}{x-1}=x$ 1. $x\frac{x-1}{x-1}=x$ 2. the fraction cancels out to 1 which makes x = x
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