Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix G - Complex Numbers - G Exercises - Page A55: 10



Work Step by Step

$\displaystyle \frac{3}{4-3i}$ We multiply the numerator and denominator by the conjugate of the denominator: $=\frac{3}{4-3i}\cdot\frac{4+3i}{4+3i}$ We use the fact that $i^2=-1$ (because $i=\sqrt{-1}$) $=\frac{12+9i}{16-9*-1}$ $=\frac{12}{25}+\frac{9}{25}i$
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