## Calculus 8th Edition

$\frac{\pi}{4},\frac{3\pi}{4},\frac{5 \pi}{4}\frac{7 \pi}{4}$
Need to find the range for $x$ for the equation $2sin^{2}x=1$ $sin^{2}x=\frac{1}{2}$ or $sinx=±\frac{1}{\sqrt 2} =±\frac{\sqrt 2}{ 2}$ Since, $sin>0$ on first and second quadrant and $sinx<0$ on third and fourth quadrant, thus, x must lie on $\frac{\pi}{4},\frac{3\pi}{4},\frac{5 \pi}{4}\frac{7 \pi}{4}$