Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.9 Numerical Integration - Preliminary Questions - Page 457: 1

Answer

$$T_1=6,\ \ \ T_2=7 $$

Work Step by Step

Given $$f(0)=3,\ f( 1)= 4,\ f(2)=3 $$ Since $n=1$, $\Delta x=\frac{2-0}{1}=2$, then \begin{align*} T_{n}&=\dfrac{1}{2}\left[f(x_0)+2f(x_1)+2f(x_2)+.....+2f(x_{n-1})+f(x_n)\right]\Delta x\\ T_{1}&=\dfrac{1}{2}\left[f(x_0) +f(x_1)\right]\Delta x\\ &=\left[f(0) +f(2)\right] \\ &\approx 6 \end{align*} and $n=2 $ $\Delta x=\frac{2-0}{2}=1$, so \begin{align*} T_{n}&=\dfrac{1}{2}\left[f(x_0)+2f(x_1)+2f(x_2)+.....+2f(x_{n-1})+f(x_n)\right]\Delta x\\ T_{1}&= \dfrac{1}{2}\left[f(x_0)+2f(x_1)+f(x_2) \right]\Delta x\\ &=\dfrac{1}{2}\left[f(0) +2f(1)+f(2)\right] \\ &\approx7 \end{align*}
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