Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.9 Numerical Integration - Exercises - Page 458: 35


$M_{10} \leq 0.01125$

Work Step by Step

We have the error $(M_N) \leq \dfrac{k_2(b-a)^3}{24N^2}$ For, $M=10$, we have: Error $M_{10} \leq \dfrac{(1)(4-1)^3}{24(10)^2} \\ \leq \dfrac{(1)(27)}{24(100)}\\ \leq \dfrac{9}{800} \\\leq 0.01125$
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