Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.5 The Method of Partial Fractions - Exercises - Page 423: 10


$$ x-\ln |x+4|+C$$

Work Step by Step

Given $$\int \frac{(x+3) d x}{x+4}$$ Since \begin{align*} \int \frac{(x+3) d x}{x+4}&=\int \frac{[(x+4) -1]d x}{x+4}\\ &=\int\left(1- \frac{1}{x+4}\right)dx\\ &= x-\ln |x+4|+C \end{align*}
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