#### Answer

$2x\sqrt{1-x^2}$

#### Work Step by Step

We have
$$\sin(2\theta)=2\sin \theta \cos\theta=2x\sqrt{1-x^2}
$$
where we used the fact that $\cos\theta =\sqrt{1-\sin^2\theta}.$

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Published by
W. H. Freeman

ISBN 10:
1464125260

ISBN 13:
978-1-46412-526-3

$2x\sqrt{1-x^2}$

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