## Calculus (3rd Edition)

$e^6$
We have $$\lim _{n \rightarrow \infty}\left(1+\frac{1}{n}\right)^{6n}=\left(\lim _{n \rightarrow \infty}\left(1+\frac{1}{n}\right)^{n}\right)^6=e^6,$$ where we used the formula $\lim _{n \rightarrow \infty}\left(1+\frac{1}{n}\right)^{n}=e$.