Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 296: 11

Answer

$V$ = $36$

Work Step by Step

$V$ = $\int_{-3}^{3}(9-x^{2})dx$ $V$ = $(9x-\frac{1}{3}x^{3})|_{-3}^3$ $V$ = $36$
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