Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 263: 28

Answer

$4$

Work Step by Step

apply chain rule and FTC $G'(x)$ = $\sqrt {x^{6}+3}(2x)$ $G'(1)$ = $\sqrt {1^{6}+3}(2\times1)$ = $4$
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