Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 244: 7


$\frac{25\pi}{4}. $

Work Step by Step

As in the figure below, the area will be the area of a quarter of a circle of radius $5$, as follows $$ \int_{0}^{5} \sqrt{25-x^2} d x= \frac{25\pi}{4}. $$
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