Chapter 4 - Differentiation - 4.1 Linear Approximation and Applications - Exercises - Page 173: 30

$s = 35$, $ΔF$ = $4.88Δs$ $ft$ $s = 55$, $ΔF$ = $7.04Δs$ $ft$

$F'(s)$ = $\frac{ΔF}{Δs}$ = $1.1+0.108s$ $ΔF$ = $F'(s)Δs$ $ΔF$ = $(1.1+0.108s)Δs$ $s = 35$ $ΔF$ = $[1.1+(0.108\times35)]Δs$ = $4.88Δs$ $ft$ $s = 55$ $ΔF$ = $[1.1+(0.108\times55)]Δs$ = $7.04Δs$ $ft$