## Calculus (3rd Edition)

every term equals to $x_0$
Since $$x_{n+1}=x_{n}-\frac{f\left(x_{n}\right)}{f^{\prime}\left(x_{n}\right)}$$ Then for $x_0= 0$ $$x_{1}=x_{0}-\frac{f\left(x_{0}\right)}{f^{\prime}\left(x_{0}\right)}=x_{0}-0=x_{0}$$ Hence, every term equals to $x_0$.