## Calculus (3rd Edition)

$f(4)=-2$, $f'(4)=3$
The equation of the tangent line is $y=f(a)+f'(a)(x-a)$ This implies that $f(4)+f'(4)(x-4)=3x-14$ From the above equation, we have $f'(4)\times x=3x$ and $[f(4)-4\times f'(4)]=-14$ Thus, we obtain $f'(4)=3$ and $f(4)=-14+(4\times3)=-2$